(4x-5)/5=(4/x)

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Solution for (4x-5)/5=(4/x) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4*x-5)/5 = 4/x // - 4/x

(4*x-5)/5-(4/x) = 0

(4*x-5)/5-4*x^-1 = 0

(4*x-5)/5-4/x = 0

(x*(4*x-5))/(5*x)+(-4*5)/(5*x) = 0

x*(4*x-5)-4*5 = 0

4*x^2-5*x-20 = 0

4*x^2-5*x-20 = 0

4*x^2-5*x-20 = 0

DELTA = (-5)^2-(-20*4*4)

DELTA = 345

DELTA > 0

x = (345^(1/2)+5)/(2*4) or x = (5-345^(1/2))/(2*4)

x = (345^(1/2)+5)/8 or x = (5-345^(1/2))/8

(x-((5-345^(1/2))/8))*(x-((345^(1/2)+5)/8)) = 0

((x-((5-345^(1/2))/8))*(x-((345^(1/2)+5)/8)))/(5*x) = 0

((x-((5-345^(1/2))/8))*(x-((345^(1/2)+5)/8)))/(5*x) = 0 // * 5*x

(x-((5-345^(1/2))/8))*(x-((345^(1/2)+5)/8)) = 0

( x-((345^(1/2)+5)/8) )

x-((345^(1/2)+5)/8) = 0 // + (345^(1/2)+5)/8

x = (345^(1/2)+5)/8

( x-((5-345^(1/2))/8) )

x-((5-345^(1/2))/8) = 0 // + (5-345^(1/2))/8

x = (5-345^(1/2))/8

x in { (345^(1/2)+5)/8, (5-345^(1/2))/8 }

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