(4x-5)/5x4x

Solution for (4x-5)/5x4x equation:

x in (-oo:+oo)

x*((4*x-5)/5) < 4*x // - 4*x

x*((4*x-5)/5)-(4*x) < 0

x*((4*x-5)/5)-4*x < 0

(x*(4*x-5))/5-4*x < 0

(x*(4*x-5))/5+(-4*5*x)/5 < 0

x*(4*x-5)-4*5*x < 0

4*x^2-25*x < 0

4*x^2-25*x = 0

x*(4*x-25) = 0

4*x-25 = 0 // + 25

4*x = 25 // : 4

x = 25/4

x*(x-25/4) = 0

(x*(x-25/4))/5 < 0

(x*(x-25/4))/5 < 0 // * 5^2

5*x*(x-25/4) < 0

( 5 )

5 < 0

x belongs to the empty set

( x-25/4 )

x-25/4 < 0 // + 25/4

x < 25/4

( x )

x+0 < 0 // - 0

x < 0

	(-oo:0)	(0:25/4)	(25/4:+oo)
5	+	+	+
x-25/4	-	-	+
x	-	+	+


x in (0:25/4)

(0:25/4)