(4x-5)=(2x+21)

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Solution for (4x-5)=(2x+21) equation: 



(4x-5)=(2x+21)

We move all terms to the left:

(4x-5)-((2x+21))=0

We get rid of parentheses

4x-((2x+21))-5=0



We calculate terms in parentheses: -((2x+21)), so:

(2x+21)

We get rid of parentheses

2x+21

Back to the equation:

-(2x+21)



We get rid of parentheses

4x-2x-21-5=0

We add all the numbers together, and all the variables

2x-26=0

We move all terms containing x to the left, all other terms to the right

2x=26

x=26/2

x=13

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