(4x-5)=(92-2x)

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Solution for (4x-5)=(92-2x) equation: 



(4x-5)=(92-2x)

We move all terms to the left:

(4x-5)-((92-2x))=0

We add all the numbers together, and all the variables

(4x-5)-((-2x+92))=0

We get rid of parentheses

4x-((-2x+92))-5=0



We calculate terms in parentheses: -((-2x+92)), so:

(-2x+92)

We get rid of parentheses

-2x+92

Back to the equation:

-(-2x+92)



We get rid of parentheses

4x+2x-92-5=0

We add all the numbers together, and all the variables

6x-97=0

We move all terms containing x to the left, all other terms to the right

6x=97

x=97/6

x=16+1/6

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