(4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)=540

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Solution for (4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)=540 equation:



(4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)=540
We move all terms to the left:
(4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)-(540)=0
We add all the numbers together, and all the variables
4x+(4x-57)+(3x+25)+(2x-3)+(3x+15)-540=0
We get rid of parentheses
4x+4x+3x+2x+3x-57+25-3+15-540=0
We add all the numbers together, and all the variables
16x-560=0
We move all terms containing x to the left, all other terms to the right
16x=560
x=560/16
x=35

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