(4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)=540

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Solution for (4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)=540 equation: 



(4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)=540

We move all terms to the left:

(4x-57)+(3x+25)+(2x-3)+(4x)+(3x+15)-(540)=0

We add all the numbers together, and all the variables

4x+(4x-57)+(3x+25)+(2x-3)+(3x+15)-540=0

We get rid of parentheses

4x+4x+3x+2x+3x-57+25-3+15-540=0

We add all the numbers together, and all the variables

16x-560=0

We move all terms containing x to the left, all other terms to the right

16x=560

x=560/16

x=35

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