(4x-6)(2x+2)=(2x+3)(4x-4)

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Solution for (4x-6)(2x+2)=(2x+3)(4x-4) equation: 



(4x-6)(2x+2)=(2x+3)(4x-4)

We move all terms to the left:

(4x-6)(2x+2)-((2x+3)(4x-4))=0

We multiply parentheses ..

(+8x^2+8x-12x-12)-((2x+3)(4x-4))=0



We calculate terms in parentheses: -((2x+3)(4x-4)), so:

(2x+3)(4x-4)

We multiply parentheses ..

(+8x^2-8x+12x-12)

We get rid of parentheses

8x^2-8x+12x-12

We add all the numbers together, and all the variables

8x^2+4x-12

Back to the equation:

-(8x^2+4x-12)



We get rid of parentheses

8x^2-8x^2+8x-12x-4x-12+12=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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