(4x-6)(4x+6)-270=0

Solution for (4x-6)(4x+6)-270=0 equation:

(4x-6)(4x+6)-270=0

We use the square of the difference formula

16x^2-36-270=0

We add all the numbers together, and all the variables

16x^2-306=0

a = 16; b = 0; c = -306;
Δ = b2-4ac
Δ = 02-4·16·(-306)
Δ = 19584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19584}=\sqrt{576*34}=\sqrt{576}*\sqrt{34}=24\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{34}}{2*16}=\frac{0-24\sqrt{34}}{32}
=-\frac{24\sqrt{34}}{32}
=-\frac{3\sqrt{34}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{34}}{2*16}=\frac{0+24\sqrt{34}}{32}
=\frac{24\sqrt{34}}{32}
=\frac{3\sqrt{34}}{4}
$