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(4x-6)(6x+3)=0
We multiply parentheses ..
(+24x^2+12x-36x-18)=0
We get rid of parentheses
24x^2+12x-36x-18=0
We add all the numbers together, and all the variables
24x^2-24x-18=0
a = 24; b = -24; c = -18;
Δ = b2-4ac
Δ = -242-4·24·(-18)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-48}{2*24}=\frac{-24}{48} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+48}{2*24}=\frac{72}{48} =1+1/2 $
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