(4x-7)(2x+6)=1x(8x+5)

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Solution for (4x-7)(2x+6)=1x(8x+5) equation: 



(4x-7)(2x+6)=1x(8x+5)

We move all terms to the left:

(4x-7)(2x+6)-(1x(8x+5))=0

We multiply parentheses ..

(+8x^2+24x-14x-42)-(1x(8x+5))=0



We calculate terms in parentheses: -(1x(8x+5)), so:

1x(8x+5)

We multiply parentheses

8x^2+5x

Back to the equation:

-(8x^2+5x)



We get rid of parentheses

8x^2-8x^2+24x-14x-5x-42=0

We add all the numbers together, and all the variables

5x-42=0

We move all terms containing x to the left, all other terms to the right

5x=42

x=42/5

x=8+2/5

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