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(4x-7)(3x+8)=5
We move all terms to the left:
(4x-7)(3x+8)-(5)=0
We multiply parentheses ..
(+12x^2+32x-21x-56)-5=0
We get rid of parentheses
12x^2+32x-21x-56-5=0
We add all the numbers together, and all the variables
12x^2+11x-61=0
a = 12; b = 11; c = -61;
Δ = b2-4ac
Δ = 112-4·12·(-61)
Δ = 3049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{3049}}{2*12}=\frac{-11-\sqrt{3049}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{3049}}{2*12}=\frac{-11+\sqrt{3049}}{24} $
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