(4x-7)(3x-5)=(6x-8)(2x-6)

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Solution for (4x-7)(3x-5)=(6x-8)(2x-6) equation: 



(4x-7)(3x-5)=(6x-8)(2x-6)

We move all terms to the left:

(4x-7)(3x-5)-((6x-8)(2x-6))=0

We multiply parentheses ..

(+12x^2-20x-21x+35)-((6x-8)(2x-6))=0



We calculate terms in parentheses: -((6x-8)(2x-6)), so:

(6x-8)(2x-6)

We multiply parentheses ..

(+12x^2-36x-16x+48)

We get rid of parentheses

12x^2-36x-16x+48

We add all the numbers together, and all the variables

12x^2-52x+48

Back to the equation:

-(12x^2-52x+48)



We get rid of parentheses

12x^2-12x^2-20x-21x+52x+35-48=0

We add all the numbers together, and all the variables

11x-13=0

We move all terms containing x to the left, all other terms to the right

11x=13

x=13/11

x=1+2/11

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