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(4x-7)(x+12)=180
We move all terms to the left:
(4x-7)(x+12)-(180)=0
We multiply parentheses ..
(+4x^2+48x-7x-84)-180=0
We get rid of parentheses
4x^2+48x-7x-84-180=0
We add all the numbers together, and all the variables
4x^2+41x-264=0
a = 4; b = 41; c = -264;
Δ = b2-4ac
Δ = 412-4·4·(-264)
Δ = 5905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{5905}}{2*4}=\frac{-41-\sqrt{5905}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{5905}}{2*4}=\frac{-41+\sqrt{5905}}{8} $
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