(4x-7)+(4x+2)=2(7x-3)+(-3x-11)

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Solution for (4x-7)+(4x+2)=2(7x-3)+(-3x-11) equation: 



(4x-7)+(4x+2)=2(7x-3)+(-3x-11)

We move all terms to the left:

(4x-7)+(4x+2)-(2(7x-3)+(-3x-11))=0

We get rid of parentheses

4x+4x-(2(7x-3)+(-3x-11))-7+2=0



We calculate terms in parentheses: -(2(7x-3)+(-3x-11)), so:

2(7x-3)+(-3x-11)

We multiply parentheses

14x+(-3x-11)-6

We get rid of parentheses

14x-3x-11-6

We add all the numbers together, and all the variables

11x-17

Back to the equation:

-(11x-17)



We add all the numbers together, and all the variables

8x-(11x-17)-5=0

We get rid of parentheses

8x-11x+17-5=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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