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(4x-7)+(4x+2)=2(7x-3)+(-3x-11)
We move all terms to the left:
(4x-7)+(4x+2)-(2(7x-3)+(-3x-11))=0
We get rid of parentheses
4x+4x-(2(7x-3)+(-3x-11))-7+2=0
We calculate terms in parentheses: -(2(7x-3)+(-3x-11)), so:We add all the numbers together, and all the variables
2(7x-3)+(-3x-11)
We multiply parentheses
14x+(-3x-11)-6
We get rid of parentheses
14x-3x-11-6
We add all the numbers together, and all the variables
11x-17
Back to the equation:
-(11x-17)
8x-(11x-17)-5=0
We get rid of parentheses
8x-11x+17-5=0
We add all the numbers together, and all the variables
-3x+12=0
We move all terms containing x to the left, all other terms to the right
-3x=-12
x=-12/-3
x=+4
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