(4x-7)+(4x-7)+(3x+4)+(3x+4)=50

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Solution for (4x-7)+(4x-7)+(3x+4)+(3x+4)=50 equation: 



(4x-7)+(4x-7)+(3x+4)+(3x+4)=50

We move all terms to the left:

(4x-7)+(4x-7)+(3x+4)+(3x+4)-(50)=0

We get rid of parentheses

4x+4x+3x+3x-7-7+4+4-50=0

We add all the numbers together, and all the variables

14x-56=0

We move all terms containing x to the left, all other terms to the right

14x=56

x=56/14

x=4

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