(4x-7)+(4x-7)+(3x+4)+3x+4)=50

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Solution for (4x-7)+(4x-7)+(3x+4)+3x+4)=50 equation: 



(4x-7)+(4x-7)+(3x+4)+3x+4)=50

We move all terms to the left:

(4x-7)+(4x-7)+(3x+4)+3x+4)-(50)=0

We add all the numbers together, and all the variables

3x+(4x-7)+(4x-7)+(3x+4)=0

We get rid of parentheses

3x+4x+4x+3x-7-7+4=0

We add all the numbers together, and all the variables

14x-10=0

We move all terms containing x to the left, all other terms to the right

14x=10

x=10/14

x=5/7

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