(4x-7)-(-4x+3)=2(5x-4)+(-x-12)

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Solution for (4x-7)-(-4x+3)=2(5x-4)+(-x-12) equation: 



(4x-7)-(-4x+3)=2(5x-4)+(-x-12)

We move all terms to the left:

(4x-7)-(-4x+3)-(2(5x-4)+(-x-12))=0

We add all the numbers together, and all the variables

(4x-7)-(-4x+3)-(2(5x-4)+(-1x-12))=0

We get rid of parentheses

4x+4x-(2(5x-4)+(-1x-12))-7-3=0



We calculate terms in parentheses: -(2(5x-4)+(-1x-12)), so:

2(5x-4)+(-1x-12)

We multiply parentheses

10x+(-1x-12)-8

We get rid of parentheses

10x-1x-12-8

We add all the numbers together, and all the variables

9x-20

Back to the equation:

-(9x-20)



We add all the numbers together, and all the variables

8x-(9x-20)-10=0

We get rid of parentheses

8x-9x+20-10=0

We add all the numbers together, and all the variables

-1x+10=0

We move all terms containing x to the left, all other terms to the right

-x=-10

x=-10/-1

x=+10

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