(4x-7)-(-4x+3)=2(5x-4)+(-x-12)

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Solution for (4x-7)-(-4x+3)=2(5x-4)+(-x-12) equation:



(4x-7)-(-4x+3)=2(5x-4)+(-x-12)
We move all terms to the left:
(4x-7)-(-4x+3)-(2(5x-4)+(-x-12))=0
We add all the numbers together, and all the variables
(4x-7)-(-4x+3)-(2(5x-4)+(-1x-12))=0
We get rid of parentheses
4x+4x-(2(5x-4)+(-1x-12))-7-3=0
We calculate terms in parentheses: -(2(5x-4)+(-1x-12)), so:
2(5x-4)+(-1x-12)
We multiply parentheses
10x+(-1x-12)-8
We get rid of parentheses
10x-1x-12-8
We add all the numbers together, and all the variables
9x-20
Back to the equation:
-(9x-20)
We add all the numbers together, and all the variables
8x-(9x-20)-10=0
We get rid of parentheses
8x-9x+20-10=0
We add all the numbers together, and all the variables
-1x+10=0
We move all terms containing x to the left, all other terms to the right
-x=-10
x=-10/-1
x=+10

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