(4x-7)-(4x+3)=2(5x-4)+(-x-11)

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Solution for (4x-7)-(4x+3)=2(5x-4)+(-x-11) equation: 



(4x-7)-(4x+3)=2(5x-4)+(-x-11)

We move all terms to the left:

(4x-7)-(4x+3)-(2(5x-4)+(-x-11))=0

We add all the numbers together, and all the variables

(4x-7)-(4x+3)-(2(5x-4)+(-1x-11))=0

We get rid of parentheses

4x-4x-(2(5x-4)+(-1x-11))-7-3=0



We calculate terms in parentheses: -(2(5x-4)+(-1x-11)), so:

2(5x-4)+(-1x-11)

We multiply parentheses

10x+(-1x-11)-8

We get rid of parentheses

10x-1x-11-8

We add all the numbers together, and all the variables

9x-19

Back to the equation:

-(9x-19)



We add all the numbers together, and all the variables

-(9x-19)-10=0

We get rid of parentheses

-9x+19-10=0

We add all the numbers together, and all the variables

-9x+9=0

We move all terms containing x to the left, all other terms to the right

-9x=-9

x=-9/-9

x=1

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