(4x-8)(4x+8)=8x(2x+4)

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Solution for (4x-8)(4x+8)=8x(2x+4) equation: 



(4x-8)(4x+8)=8x(2x+4)

We move all terms to the left:

(4x-8)(4x+8)-(8x(2x+4))=0

We use the square of the difference formula

16x^2-(8x(2x+4))-64=0



We calculate terms in parentheses: -(8x(2x+4)), so:

8x(2x+4)

We multiply parentheses

16x^2+32x

Back to the equation:

-(16x^2+32x)



We get rid of parentheses

16x^2-16x^2-32x-64=0

We add all the numbers together, and all the variables

-32x-64=0

We move all terms containing x to the left, all other terms to the right

-32x=64

x=64/-32

x=-2

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