(4x-8)=(2x+78)=38

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Solution for (4x-8)=(2x+78)=38 equation: 



(4x-8)=(2x+78)=38

We move all terms to the left:

(4x-8)-((2x+78))=0

We get rid of parentheses

4x-((2x+78))-8=0



We calculate terms in parentheses: -((2x+78)), so:

(2x+78)

We get rid of parentheses

2x+78

Back to the equation:

-(2x+78)



We get rid of parentheses

4x-2x-78-8=0

We add all the numbers together, and all the variables

2x-86=0

We move all terms containing x to the left, all other terms to the right

2x=86

x=86/2

x=43

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