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(4x-9)(2x+6)=x
We move all terms to the left:
(4x-9)(2x+6)-(x)=0
We add all the numbers together, and all the variables
-1x+(4x-9)(2x+6)=0
We multiply parentheses ..
(+8x^2+24x-18x-54)-1x=0
We get rid of parentheses
8x^2+24x-18x-1x-54=0
We add all the numbers together, and all the variables
8x^2+5x-54=0
a = 8; b = 5; c = -54;
Δ = b2-4ac
Δ = 52-4·8·(-54)
Δ = 1753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1753}}{2*8}=\frac{-5-\sqrt{1753}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1753}}{2*8}=\frac{-5+\sqrt{1753}}{16} $
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