(4x-9)/6=x-(2x+7)/2

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Solution for (4x-9)/6=x-(2x+7)/2 equation: 



(4x-9)/6=x-(2x+7)/2

We move all terms to the left:

(4x-9)/6-(x-(2x+7)/2)=0

We calculate fractions


4x/()+(-(x-(2x+7)*6)/()=0



We calculate terms in parentheses: +(-(x-(2x+7)*6)/(), so:

-(x-(2x+7)*6)/(

We multiply all the terms by the denominator


-(x-(2x+7)*6)



We calculate terms in parentheses: -(x-(2x+7)*6), so:

x-(2x+7)*6

We multiply parentheses

x-12x-42

We add all the numbers together, and all the variables

-11x-42

Back to the equation:

-(-11x-42)



We get rid of parentheses

11x+42

Back to the equation:

+(11x+42)



We get rid of parentheses

4x/()+11x+42=0

We multiply all the terms by the denominator


4x+11x*()+42*()=0

We add all the numbers together, and all the variables

4x+11x*()=0

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