(4x/(2x+3))+(6/(2x+3))

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Solution for (4x/(2x+3))+(6/(2x+3)) equation: 


D( x )

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x in (-oo:-3/2) U (-3/2:+oo)

(4*x)/(2*x+3)+6/(2*x+3) = 0

4*x+6 = 0

(4*x+6)/(2*x+3) = 0

(4*x+6)/(2*x+3) = 0 // * 2*x+3

4*x+6 = 0

4*x+6 = 0 // - 6

4*x = -6 // : 4

x = -6/4

x = -3/2

x in { -3/2} 

x belongs to the empty set

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