(4x/3)3=(2x/3)+3

Solution for (4x/3)3=(2x/3)+3 equation:

(4x/3)3=(2x/3)+3

We move all terms to the left:

(4x/3)3-((2x/3)+3)=0

We add all the numbers together, and all the variables

(+4x/3)3-((+2x/3)+3)=0

We multiply parentheses

12x-((+2x/3)+3)=0

We multiply all the terms by the denominator


12x*3)+3)-((+2x=0

We add all the numbers together, and all the variables

2x+12x*3)+3)-((=0

Wy multiply elements

36x^2+2x=0

a = 36; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·36·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*36}=\frac{-4}{72}
=-1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*36}=\frac{0}{72}
=0
$