(4x/35)=(10/49

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Solution for (4x/35)=(10/49 equation:



(4x/35)=(10/49
We move all terms to the left:
(4x/35)-((10/49)=0
We add all the numbers together, and all the variables
(+4x/35)-((+10/49)=0
We get rid of parentheses
4x/35-((+10/49)=0
We calculate fractions
196x^2/()+()/()=0
We add all the numbers together, and all the variables
196x^2/()+1=0
We multiply all the terms by the denominator
196x^2+1*()=0
We add all the numbers together, and all the variables
196x^2=0
a = 196; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·196·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{392}=0$

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