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(4x^2+8)=(4x^2+2x-2)
We move all terms to the left:
(4x^2+8)-((4x^2+2x-2))=0
We get rid of parentheses
4x^2-((4x^2+2x-2))+8=0
We calculate terms in parentheses: -((4x^2+2x-2)), so:We get rid of parentheses
(4x^2+2x-2)
We get rid of parentheses
4x^2+2x-2
Back to the equation:
-(4x^2+2x-2)
4x^2-4x^2-2x+2+8=0
We add all the numbers together, and all the variables
-2x+10=0
We move all terms containing x to the left, all other terms to the right
-2x=-10
x=-10/-2
x=+5
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