(4x2+x)=(x2+2x)

Solution for (4x2+x)=(x2+2x) equation:

(4x^2+x)=(x2+2x)

We move all terms to the left:

(4x^2+x)-((x2+2x))=0

We add all the numbers together, and all the variables

-((+x^2+2x))+(4x^2+x)=0

We get rid of parentheses

-((+x^2+2x))+4x^2+x=0


We calculate terms in parentheses: -((+x^2+2x)), so:

(+x^2+2x)

We get rid of parentheses

x^2+2x

Back to the equation:

-(x^2+2x)


We add all the numbers together, and all the variables

4x^2+x-(x^2+2x)=0

We get rid of parentheses

4x^2-x^2+x-2x=0

We add all the numbers together, and all the variables

3x^2-1x=0

a = 3; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·3·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*3}=\frac{2}{6}
=1/3
$