(4x2-6x+7)+(-19x2+(7x+5)=)

Solution for (4x2-6x+7)+(-19x2+(7x+5)=) equation:

(4x^2-6x+7)+(-19x^2+(7x+5)=)

We move all terms to the left:

(4x^2-6x+7)+(-19x^2+(7x+5)-())=0

We get rid of parentheses

(-19x^2+(7x+5)-())+4x^2-6x+7=0


We calculate terms in parentheses: +(-19x^2+(7x+5)-()), so:

-19x^2+(7x+5)-()

We add all the numbers together, and all the variables

-19x^2+(7x+5)

We get rid of parentheses

-19x^2+7x+5

Back to the equation:

+(-19x^2+7x+5)


We add all the numbers together, and all the variables

4x^2+(-19x^2+7x+5)-6x+7=0

We get rid of parentheses

4x^2-19x^2+7x-6x+5+7=0

We add all the numbers together, and all the variables

-15x^2+x+12=0

a = -15; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·(-15)·12
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{721}}{2*-15}=\frac{-1-\sqrt{721}}{-30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{721}}{2*-15}=\frac{-1+\sqrt{721}}{-30}
$