(4x=1)+(2x-2)=125

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Solution for (4x=1)+(2x-2)=125 equation: 



(4x=1)+(2x-2)=125

We move all terms to the left:

(4x-(1)+(2x-2))=0



We calculate terms in parentheses: +(4x-1+(2x-2)), so:

4x-1+(2x-2)

determiningTheFunctionDomain
4x+(2x-2)-1

We get rid of parentheses

4x+2x-2-1

We add all the numbers together, and all the variables

6x-3

Back to the equation:

+(6x-3)



We get rid of parentheses

6x-3=0

We move all terms containing x to the left, all other terms to the right

6x=3

x=3/6

x=1/2

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