(4x=2)(3x+4)=

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Solution for (4x=2)(3x+4)= equation: 



(4x=2)(3x+4)=

We move all terms to the left:

(4x-(2)(3x+4))=0



We calculate terms in parentheses: +(4x-2(3x+4)), so:

4x-2(3x+4)

We multiply parentheses

4x-6x-8

We add all the numbers together, and all the variables

-2x-8

Back to the equation:

+(-2x-8)



We get rid of parentheses

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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