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(4x=3(x+4))
We move all terms to the left:
(4x-(3(x+4)))=0
We calculate terms in parentheses: +(4x-(3(x+4))), so:We get rid of parentheses
4x-(3(x+4))
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
4x-3x-12
We add all the numbers together, and all the variables
x-12
Back to the equation:
+(x-12)
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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