(4x=5)(4x-5)=0

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Solution for (4x=5)(4x-5)=0 equation: 



(4x=5)(4x-5)=0

We move all terms to the left:

(4x-(5)(4x-5))=0



We calculate terms in parentheses: +(4x-5(4x-5)), so:

4x-5(4x-5)

We multiply parentheses

4x-20x+25

We add all the numbers together, and all the variables

-16x+25

Back to the equation:

+(-16x+25)



We get rid of parentheses

-16x+25=0

We move all terms containing x to the left, all other terms to the right

-16x=-25

x=-25/-16

x=1+9/16

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