(4y+1)+(y-4)=12

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Solution for (4y+1)+(y-4)=12 equation:


Simplifying
(4y + 1) + (y + -4) = 12

Reorder the terms:
(1 + 4y) + (y + -4) = 12

Remove parenthesis around (1 + 4y)
1 + 4y + (y + -4) = 12

Reorder the terms:
1 + 4y + (-4 + y) = 12

Remove parenthesis around (-4 + y)
1 + 4y + -4 + y = 12

Reorder the terms:
1 + -4 + 4y + y = 12

Combine like terms: 1 + -4 = -3
-3 + 4y + y = 12

Combine like terms: 4y + y = 5y
-3 + 5y = 12

Solving
-3 + 5y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 5y = 12 + 3

Combine like terms: -3 + 3 = 0
0 + 5y = 12 + 3
5y = 12 + 3

Combine like terms: 12 + 3 = 15
5y = 15

Divide each side by '5'.
y = 3

Simplifying
y = 3

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