(4y+1/y-2)-(y-2/y-2)

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Solution for (4y+1/y-2)-(y-2/y-2) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

4*y-y+1/y+2/y-2+2 = 0

3*y^1+3*y^-1 = 0

(3*y^2+3*y^0)/(y^1) = 0 // * y^2

y^1*(3*y^2+3*y^0) = 0

y^1

3*y^2+3 = 0

3*y^2+3 = 0

DELTA = 0^2-(3*3*4)

DELTA = -36

DELTA < 0

y in { } 

y belongs to the empty set

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