(4y+10)y-(10y)=1440000

Solution for (4y+10)y-(10y)=1440000 equation:

(4y+10)y-(10y)=1440000

We move all terms to the left:

(4y+10)y-(10y)-(1440000)=0

We add all the numbers together, and all the variables

-10y+(4y+10)y-1440000=0

We multiply parentheses

4y^2-10y+10y-1440000=0

We add all the numbers together, and all the variables

4y^2-1440000=0

a = 4; b = 0; c = -1440000;
Δ = b2-4ac
Δ = 02-4·4·(-1440000)
Δ = 23040000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23040000}=4800$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4800}{2*4}=\frac{-4800}{8}
=-600
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4800}{2*4}=\frac{4800}{8}
=600
$