(4y+2)+5y=202

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Solution for (4y+2)+5y=202 equation: 



(4y+2)+5y=202

We move all terms to the left:

(4y+2)+5y-(202)=0

We add all the numbers together, and all the variables

5y+(4y+2)-202=0

We get rid of parentheses

5y+4y+2-202=0

We add all the numbers together, and all the variables

9y-200=0

We move all terms containing y to the left, all other terms to the right

9y=200

y=200/9

y=22+2/9

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