(4y+2)2y=-10

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Solution for (4y+2)2y=-10 equation:



(4y+2)2y=-10
We move all terms to the left:
(4y+2)2y-(-10)=0
We add all the numbers together, and all the variables
(4y+2)2y+10=0
We multiply parentheses
8y^2+4y+10=0
a = 8; b = 4; c = +10;
Δ = b2-4ac
Δ = 42-4·8·10
Δ = -304
Delta is less than zero, so there is no solution for the equation

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