(4y+2)=(3y+7)

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Solution for (4y+2)=(3y+7) equation: 



(4y+2)=(3y+7)

We move all terms to the left:

(4y+2)-((3y+7))=0

We get rid of parentheses

4y-((3y+7))+2=0



We calculate terms in parentheses: -((3y+7)), so:

(3y+7)

We get rid of parentheses

3y+7

Back to the equation:

-(3y+7)



We get rid of parentheses

4y-3y-7+2=0

We add all the numbers together, and all the variables

y-5=0

We move all terms containing y to the left, all other terms to the right

y=5

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