(4y+25)=(3y+20)

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Solution for (4y+25)=(3y+20) equation: 



(4y+25)=(3y+20)

We move all terms to the left:

(4y+25)-((3y+20))=0

We get rid of parentheses

4y-((3y+20))+25=0



We calculate terms in parentheses: -((3y+20)), so:

(3y+20)

We get rid of parentheses

3y+20

Back to the equation:

-(3y+20)



We get rid of parentheses

4y-3y-20+25=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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