(4y+3)*4y=76

Solution for (4y+3)*4y=76 equation:

(4y+3)*4y=76

We move all terms to the left:

(4y+3)*4y-(76)=0

We multiply parentheses

16y^2+12y-76=0

a = 16; b = 12; c = -76;
Δ = b2-4ac
Δ = 122-4·16·(-76)
Δ = 5008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5008}=\sqrt{16*313}=\sqrt{16}*\sqrt{313}=4\sqrt{313}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{313}}{2*16}=\frac{-12-4\sqrt{313}}{32}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{313}}{2*16}=\frac{-12+4\sqrt{313}}{32}
$