(4y+3)+2y=1

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Solution for (4y+3)+2y=1 equation:



(4y+3)+2y=1
We move all terms to the left:
(4y+3)+2y-(1)=0
We add all the numbers together, and all the variables
2y+(4y+3)-1=0
We get rid of parentheses
2y+4y+3-1=0
We add all the numbers together, and all the variables
6y+2=0
We move all terms containing y to the left, all other terms to the right
6y=-2
y=-2/6
y=-1/3

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