(4y+3)/(2y-1)=3/5

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Solution for (4y+3)/(2y-1)=3/5 equation: 


D( y )

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0 // + 1

2*y = 1 // : 2

y = 1/2

y in (-oo:1/2) U (1/2:+oo)

(4*y+3)/(2*y-1) = 3/5 // - 3/5

(4*y+3)/(2*y-1)-(3/5) = 0

(4*y+3)/(2*y-1)-3/5 = 0

(5*(4*y+3))/(5*(2*y-1))+(-3*(2*y-1))/(5*(2*y-1)) = 0

5*(4*y+3)-3*(2*y-1) = 0

14*y+18 = 0

(14*y+18)/(5*(2*y-1)) = 0

(14*y+18)/(5*(2*y-1)) = 0 // * 5*(2*y-1)

14*y+18 = 0

14*y+18 = 0 // - 18

14*y = -18 // : 14

y = -18/14

y = -9/7

y = -9/7

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