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(4y+3)=(4y-3)
We move all terms to the left:
(4y+3)-((4y-3))=0
We get rid of parentheses
4y-((4y-3))+3=0
We calculate terms in parentheses: -((4y-3)), so:We get rid of parentheses
(4y-3)
We get rid of parentheses
4y-3
Back to the equation:
-(4y-3)
4y-4y+3+3=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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