(4y+3)=(6y-29)

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Solution for (4y+3)=(6y-29) equation: 



(4y+3)=(6y-29)

We move all terms to the left:

(4y+3)-((6y-29))=0

We get rid of parentheses

4y-((6y-29))+3=0



We calculate terms in parentheses: -((6y-29)), so:

(6y-29)

We get rid of parentheses

6y-29

Back to the equation:

-(6y-29)



We get rid of parentheses

4y-6y+29+3=0

We add all the numbers together, and all the variables

-2y+32=0

We move all terms containing y to the left, all other terms to the right

-2y=-32

y=-32/-2

y=+16

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