(4y+4)-(2+3y)=10

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Solution for (4y+4)-(2+3y)=10 equation: 


Simplifying
(4y + 4) + -1(2 + 3y) = 10

Reorder the terms:
(4 + 4y) + -1(2 + 3y) = 10

Remove parenthesis around (4 + 4y)
4 + 4y + -1(2 + 3y) = 10
4 + 4y + (2 * -1 + 3y * -1) = 10
4 + 4y + (-2 + -3y) = 10

Reorder the terms:
4 + -2 + 4y + -3y = 10

Combine like terms: 4 + -2 = 2
2 + 4y + -3y = 10

Combine like terms: 4y + -3y = 1y
2 + 1y = 10

Solving
2 + 1y = 10

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 1y = 10 + -2

Combine like terms: 2 + -2 = 0
0 + 1y = 10 + -2
1y = 10 + -2

Combine like terms: 10 + -2 = 8
1y = 8

Divide each side by '1'.
y = 8

Simplifying
y = 8

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