(4y+4)-(3-3y)=8

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Solution for (4y+4)-(3-3y)=8 equation: 



(4y+4)-(3-3y)=8

We move all terms to the left:

(4y+4)-(3-3y)-(8)=0

We add all the numbers together, and all the variables

(4y+4)-(-3y+3)-8=0

We get rid of parentheses

4y+3y+4-3-8=0

We add all the numbers together, and all the variables

7y-7=0

We move all terms containing y to the left, all other terms to the right

7y=7

y=7/7

y=1

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