(4y+44)=(3y+66)

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Solution for (4y+44)=(3y+66) equation: 



(4y+44)=(3y+66)

We move all terms to the left:

(4y+44)-((3y+66))=0

We get rid of parentheses

4y-((3y+66))+44=0



We calculate terms in parentheses: -((3y+66)), so:

(3y+66)

We get rid of parentheses

3y+66

Back to the equation:

-(3y+66)



We get rid of parentheses

4y-3y-66+44=0

We add all the numbers together, and all the variables

y-22=0

We move all terms containing y to the left, all other terms to the right

y=22

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