(4y+5)(7-y)=0

Solution for (4y+5)(7-y)=0 equation:

(4y+5)(7-y)=0

We add all the numbers together, and all the variables

(4y+5)(-1y+7)=0

We multiply parentheses ..

(-4y^2+28y-5y+35)=0

We get rid of parentheses

-4y^2+28y-5y+35=0

We add all the numbers together, and all the variables

-4y^2+23y+35=0

a = -4; b = 23; c = +35;
Δ = b2-4ac
Δ = 232-4·(-4)·35
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-33}{2*-4}=\frac{-56}{-8}
=+7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+33}{2*-4}=\frac{10}{-8}
=-1+1/4
$