(4y+5)-(4+3y)=2

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Solution for (4y+5)-(4+3y)=2 equation:


Simplifying
(4y + 5) + -1(4 + 3y) = 2

Reorder the terms:
(5 + 4y) + -1(4 + 3y) = 2

Remove parenthesis around (5 + 4y)
5 + 4y + -1(4 + 3y) = 2
5 + 4y + (4 * -1 + 3y * -1) = 2
5 + 4y + (-4 + -3y) = 2

Reorder the terms:
5 + -4 + 4y + -3y = 2

Combine like terms: 5 + -4 = 1
1 + 4y + -3y = 2

Combine like terms: 4y + -3y = 1y
1 + 1y = 2

Solving
1 + 1y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 1y = 2 + -1

Combine like terms: 1 + -1 = 0
0 + 1y = 2 + -1
1y = 2 + -1

Combine like terms: 2 + -1 = 1
1y = 1

Divide each side by '1'.
y = 1

Simplifying
y = 1

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