(4y+6)(4+y)=0

Solution for (4y+6)(4+y)=0 equation:

(4y+6)(4+y)=0

We add all the numbers together, and all the variables

(4y+6)(y+4)=0

We multiply parentheses ..

(+4y^2+16y+6y+24)=0

We get rid of parentheses

4y^2+16y+6y+24=0

We add all the numbers together, and all the variables

4y^2+22y+24=0

a = 4; b = 22; c = +24;
Δ = b2-4ac
Δ = 222-4·4·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-10}{2*4}=\frac{-32}{8}
=-4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+10}{2*4}=\frac{-12}{8}
=-1+1/2
$