(4y+6)+(7y-7)+(20y-11)=360

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Solution for (4y+6)+(7y-7)+(20y-11)=360 equation: 



(4y+6)+(7y-7)+(20y-11)=360

We move all terms to the left:

(4y+6)+(7y-7)+(20y-11)-(360)=0

We get rid of parentheses

4y+7y+20y+6-7-11-360=0

We add all the numbers together, and all the variables

31y-372=0

We move all terms containing y to the left, all other terms to the right

31y=372

y=372/31

y=12

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